CSSStyleDeclaration.getPropertyValue()

The CSSStyleDeclaration.getPropertyValue() method interface returns a DOMString containing the value of a specified CSS property.

Syntax

var value = style.getPropertyValue(property);

Parameters

  • property is a DOMString representing the property name to be checked.

Return value

  • value is a DOMString containing the value of the property. If not set, returns the empty string.

Example

The following JavaScript code checks whether margin is marked as important in a CSS selector rule:

var declaration = document.styleSheets[0].rules[0].style;
var value = declaration.getPropertyValue('margin'); // "1px 2px"

Specifications

Specification Status Comment
CSS Object Model (CSSOM)
The definition of 'CSSStyleDeclaration.getPropertyValue()' in that specification.
Working Draft  
Document Object Model (DOM) Level 2 Style Specification
The definition of 'CSSStyleDeclaration' in that specification.
Recommendation  

Browser compatibility

Feature Chrome Edge Firefox (Gecko) Internet Explorer Opera Safari (WebKit)
Basic support (Yes) (Yes) (Yes) (Yes) (Yes) (Yes)
Feature Android Edge Firefox Mobile (Gecko) IE Mobile Opera Mobile Safari Mobile Chrome for Android
Basic support (Yes) (Yes) (Yes) (Yes) (Yes) (Yes) (Yes)

Document Tags and Contributors

 Contributors to this page: bunnybooboo, Qantas94Heavy
 Last updated by: bunnybooboo,