Set.prototype.delete()

The delete() method removes the specified element from a Set object.

Syntax

mySet.delete(value);

Parameters

value

Required. The value of the element to remove from the Set object.

Return value

true if an element in the Set object has been removed successfully; otherwise false.

Examples

Using the delete method

var mySet = new Set();
mySet.add('foo');
mySet.delete('bar'); // Returns false. No "bar" element found to be deleted.
mySet.delete('foo'); // Returns true.  Successfully removed.
mySet.has('foo');    // Returns false. The "foo" element is no longer present.

Let's checkout below how to delete an Object from a Set.

var setObj = new Set(); // Create a New Set.
setObj.add({x: 10, y: 20}); // Add object in the set.
setObj.add({x: 20, y: 30}); // Add object in the set.
// Delete any point with `x > 10`.
setObj.forEach(function(point){
  if(point.x > 10){
    setObj.delete(point)
  }
})

Specifications

Browser compatibility

See also

• Set
• Set.prototype.clear()