DataTransferItem.getAsFile()

If the item is a file, the DataTransferItem.getAsFile() method returns the drag data item's File object. If the item is not a file, this method returns null.

Syntax

File = DataTransferItem.getAsFile();

Parameters

None.

Return value

File

If the drag data item is a file, a File object is returned; otherwise null is returned.

Example

This example shows the use of the getAsFile() method in a drop event handler.

function drop_handler(ev) {
 console.log("Drop");
 ev.preventDefault();
 var data = event.dataTransfer.items;
 for (var i = 0; i < data.length; i += 1) {
   if ((data[i].kind == 'string') && 
       (data[i].type.match('^text/plain'))) {
     // This item is the target node
     data[i].getAsString(function (s){
       ev.target.appendChild(document.getElementById(s)); 
     });
   } else if ((data[i].kind == 'string') && 
              (data[i].type.match('^text/html'))) {
     // Drag data item is HTML
     console.log("... Drop: HTML");
   } else if ((data[i].kind == 'string') && 
              (data[i].type.match('^text/uri-list'))) {
     // Drag data item is URI
     console.log("... Drop: URI");
   } else if ((data[i].kind == 'file') && 
              (data[i].type.match('^image/'))) {
     // Drag data item is an image file
     var f = data[i].getAsFile();
     console.log("... Drop: File ");
   }
 }
}

Specifications

Browser compatibility

See also

• DataTransfer.files()