Troubleshooting

This section contains examples of problems developers might encounter when using reflection to locate, invoke, or get information about methods.

NoSuchMethodException Due to Type Erasure

The MethodTrouble example illustrates what happens when type erasure is not taken into consideration by code which searches for a particular method in a class.


import java.lang.reflect.Method;

public class MethodTrouble<T>  {
    public void lookup(T t) {}
    public void find(Integer i) {}

    public static void main(String... args) {
	try {
	    String mName = args[0];
	    Class cArg = Class.forName(args[1]);
	    Class<?> c = (new MethodTrouble<Integer>()).getClass();
	    Method m = c.getMethod(mName, cArg);
	    System.out.format("Found:%n  %s%n", m.toGenericString());

        // production code should handle these exceptions more gracefully
	} catch (NoSuchMethodException x) {
	    x.printStackTrace();
	} catch (ClassNotFoundException x) {
	    x.printStackTrace();
	}
    }
}

$ java MethodTrouble lookup java.lang.Integer
java.lang.NoSuchMethodException: MethodTrouble.lookup(java.lang.Integer)
        at java.lang.Class.getMethod(Class.java:1605)
        at MethodTrouble.main(MethodTrouble.java:12)

$ java MethodTrouble lookup java.lang.Object
Found:
  public void MethodTrouble.lookup(T)

When a method is declared with a generic parameter type, the compiler will replace the generic type with its upper bound, in this case, the upper bound of T is Object. Thus, when the code searches for lookup(Integer), no method is found, despite the fact that the instance of MethodTrouble was created as follows:

Class<?> c = (new MethodTrouble<Integer>()).getClass();

Searching for lookup(Object) succeeds as expected.

$ java MethodTrouble find java.lang.Integer
Found:
  public void MethodTrouble.find(java.lang.Integer)
$ java MethodTrouble find java.lang.Object
java.lang.NoSuchMethodException: MethodTrouble.find(java.lang.Object)
        at java.lang.Class.getMethod(Class.java:1605)
        at MethodTrouble.main(MethodTrouble.java:12)

In this case, find() has no generic parameters, so the parameter types searched for by getMethod() must match exactly.

Tip: Always pass the upper bound of the parameterized type when searching for a method.

IllegalAccessException when Invoking a Method

An IllegalAccessException is thrown if an attempt is made to invoke a private or otherwise inaccessible method.

The MethodTroubleAgain example shows a typical stack trace which results from trying to invoke a private method in an another class.


import java.lang.reflect.InvocationTargetException;
import java.lang.reflect.Method;

class AnotherClass {
    private void m() {}
}

public class MethodTroubleAgain {
    public static void main(String... args) {
	AnotherClass ac = new AnotherClass();
	try {
	    Class<?> c = ac.getClass();
 	    Method m = c.getDeclaredMethod("m");
//  	    m.setAccessible(true);      // solution
 	    Object o = m.invoke(ac);    // IllegalAccessException

        // production code should handle these exceptions more gracefully
	} catch (NoSuchMethodException x) {
	    x.printStackTrace();
	} catch (InvocationTargetException x) {
	    x.printStackTrace();
	} catch (IllegalAccessException x) {
	    x.printStackTrace();
	}
    }
}

The stack trace for the exception thrown follows.

$ java MethodTroubleAgain
java.lang.IllegalAccessException: Class MethodTroubleAgain can not access a
  member of class AnotherClass with modifiers "private"
        at sun.reflect.Reflection.ensureMemberAccess(Reflection.java:65)
        at java.lang.reflect.Method.invoke(Method.java:588)
        at MethodTroubleAgain.main(MethodTroubleAgain.java:15)

Tip: An access restriction exists which prevents reflective invocation of methods which normally would not be accessible via direct invocation. (This includes---but is not limited to---private methods in a separate class and public methods in a separate private class.) However, Method is declared to extend AccessibleObject which provides the ability to suppress this check via AccessibleObject.setAccessible(). If it succeeds, then subsequent invocations of this method object will not fail due to this problem.

IllegalArgumentException from Method.invoke()

Method.invoke() has been retrofitted to be a variable-arity method. This is an enormous convenience, however it can lead to unexpected behavior. The MethodTroubleToo example shows various ways in which Method.invoke() can produce confusing results.


import java.lang.reflect.Method;

public class MethodTroubleToo {
    public void ping() { System.out.format("PONG!%n"); }

    public static void main(String... args) {
	try {
	    MethodTroubleToo mtt = new MethodTroubleToo();
	    Method m = MethodTroubleToo.class.getMethod("ping");

 	    switch(Integer.parseInt(args[0])) {
	    case 0:
  		m.invoke(mtt);                 // works
		break;
	    case 1:
 		m.invoke(mtt, null);           // works (expect compiler warning)
		break;
	    case 2:
		Object arg2 = null;
		m.invoke(mtt, arg2);           // IllegalArgumentException
		break;
	    case 3:
		m.invoke(mtt, new Object[0]);  // works
		break;
	    case 4:
		Object arg4 = new Object[0];
		m.invoke(mtt, arg4);           // IllegalArgumentException
		break;
	    default:
		System.out.format("Test not found%n");
	    }

        // production code should handle these exceptions more gracefully
	} catch (Exception x) {
	    x.printStackTrace();
	}
    }
}

$ java MethodTroubleToo 0
PONG!

Since all of the parameters of Method.invoke() are optional except for the first, they can be omitted when the method to be invoked has no parameters.

$ java MethodTroubleToo 1
PONG!

The code in this case generates this compiler warning because null is ambiguous.

$ javac MethodTroubleToo.java
MethodTroubleToo.java:16: warning: non-varargs call of varargs method with
  inexact argument type for last parameter;
 		m.invoke(mtt, null);           // works (expect compiler warning)
 		              ^
  cast to Object for a varargs call
  cast to Object[] for a non-varargs call and to suppress this warning
1 warning

It is not possible to determine whether null represents an empty array of arguments or a first argument of null.

$ java MethodTroubleToo 2
java.lang.IllegalArgumentException: wrong number of arguments
        at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
        at sun.reflect.NativeMethodAccessorImpl.invoke
          (NativeMethodAccessorImpl.java:39)
        at sun.reflect.DelegatingMethodAccessorImpl.invoke
          (DelegatingMethodAccessorImpl.java:25)
        at java.lang.reflect.Method.invoke(Method.java:597)
        at MethodTroubleToo.main(MethodTroubleToo.java:21)

This fails despite the fact that the argument is null, because the type is a Object and ping() expects no arguments at all.

$ java MethodTroubleToo 3
PONG!

This works because new Object[0] creates an empty array, and to a varargs method, this is equivalent to not passing any of the optional arguments.

$ java MethodTroubleToo 4
java.lang.IllegalArgumentException: wrong number of arguments
        at sun.reflect.NativeMethodAccessorImpl.invoke0
          (Native Method)
        at sun.reflect.NativeMethodAccessorImpl.invoke
          (NativeMethodAccessorImpl.java:39)
        at sun.reflect.DelegatingMethodAccessorImpl.invoke
          (DelegatingMethodAccessorImpl.java:25)
        at java.lang.reflect.Method.invoke(Method.java:597)
        at MethodTroubleToo.main(MethodTroubleToo.java:28)

Unlike the previous example, if the empty array is stored in an Object, then it is treated as an Object. This fails for the same reason that case 2 fails, ping() does not expect an argument.

Tip: When a method foo(Object... o) is declared the compiler will put all of the arguments passed to foo() in an array of type Object. The implementation of foo() is the same as if it were declared foo(Object[] o). Understanding this may help avoid the types of problems illustrated above.

InvocationTargetException when Invoked Method Fails

An InvocationTargetException wraps all exceptions (checked and unchecked) produced when a method object is invoked. The MethodTroubleReturns example shows how to retrieve the original exception thrown by the invoked method.


import java.lang.reflect.InvocationTargetException;
import java.lang.reflect.Method;

public class MethodTroubleReturns {
    private void drinkMe(int liters) {
	if (liters < 0)
	    throw new IllegalArgumentException("I can't drink a negative amount of liquid");
    }

    public static void main(String... args) {
	try {
	    MethodTroubleReturns mtr  = new MethodTroubleReturns();
 	    Class<?> c = mtr.getClass();
   	    Method m = c.getDeclaredMethod("drinkMe", int.class);
	    m.invoke(mtr, -1);

        // production code should handle these exceptions more gracefully
	} catch (InvocationTargetException x) {
	    Throwable cause = x.getCause();
	    System.err.format("drinkMe() failed: %s%n", cause.getMessage());
	} catch (Exception x) {
	    x.printStackTrace();
	}
    }
}

$ java MethodTroubleReturns
drinkMe() failed: I can't drink a negative amount of liquid

Tip: If an InvocationTargetException is thrown, the method was invoked. Diagnosis of the problem would be the same as if the method was called directly and threw the exception that is retrieved by getCause(). This exception does not indicate a problem with the reflection package or its usage.

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