while statement, but evaluates its expression at the bottom of the loop.for statement?
Answer:
for ( ; ; ) {
}
while statement?
Answer:
while (true) {
}
if (aNumber >= 0)
if (aNumber == 0)
System.out.println("first string");
else
System.out.println("second string");
System.out.println("third string");
aNumber is 3?
Solution:
second string third string
aNumber 3. What is the output of the program? Is it what you predicted? Explain why the output is what it is. In other words, what is the control flow for the code snippet?
Solution:
NestedIf
second string third string
if statement. The second if statement's test fails because 3 is not equal to 0. Thus, the else clause executes (since it's attached to the second if statement). Thus, second string is displayed. The final println is completely outside of any if statement, so it always gets executed, and thus third string is always displayed.Solution:
if (aNumber >= 0)
if (aNumber == 0)
System.out.println("first string");
else
System.out.println("second string");
System.out.println("third string");
{ and } to further clarify the code and reduce the possibility of errors by future maintainers of the code.
Solution:
if (aNumber >= 0) {
if (aNumber == 0) {
System.out.println("first string");
} else {
System.out.println("second string");
}
}
System.out.println("third string");