Oracle® Database SQL Language Reference 11g Release 2 (11.2) Part Number E26088-02 |
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See Also:
"Analytic Functions" for information on syntax, semantics, and restrictions, including valid forms ofexpr
FIRST_VALUE
is an analytic function. It returns the first value in an ordered set of values. If the first value in the set is null, then the function returns NULL
unless you specify IGNORE NULLS
. This setting is useful for data densification.
Note:
The two forms of this syntax have the same behavior. The top branch is the ANSI format, which Oracle recommends. The bottom branch is deprecated but is supported for backward compatibility.{RESPECT
| IGNORE
} NULLS
determines whether null values of expr
are included in or eliminated from the calculation. The default is RESPECT
NULLS
. If you specify IGNORE NULLS
, then FIRST_VALUE
returns the first non-null value in the set, or NULL
if all values are null. Refer to "Using Partitioned Outer Joins: Examples" for an example of data densification.
You cannot nest analytic functions by using FIRST_VALUE
or any other analytic function for expr
. However, you can use other built-in function expressions for expr
. Refer to "About SQL Expressions" for information on valid forms of expr
.
The following example selects, for each employee in Department 90, the name of the employee with the lowest salary.
SELECT department_id, last_name, salary, FIRST_VALUE(last_name) OVER (ORDER BY salary ASC ROWS UNBOUNDED PRECEDING) AS lowest_sal FROM (SELECT * FROM employees WHERE department_id = 90 ORDER BY employee_id) ORDER BY last_name; DEPARTMENT_ID LAST_NAME SALARY LOWEST_SAL ------------- ------------------------- ---------- ------------------------- 90 De Haan 17000 Kochhar 90 King 24000 Kochhar 90 Kochhar 17000 Kochhar
The example illustrates the nondeterministic nature of the FIRST_VALUE
function. Kochhar and DeHaan have the same salary, so are in adjacent rows. Kochhar appears first because the rows returned by the subquery are ordered by employee_id
. However, if the rows returned by the subquery are ordered by employee_id
in descending order, as in the next example, then the function returns a different value:
SELECT department_id, last_name, salary, FIRST_VALUE(last_name) OVER (ORDER BY salary ASC ROWS UNBOUNDED PRECEDING) AS fv FROM (SELECT * FROM employees WHERE department_id = 90 ORDER by employee_id DESC) ORDER BY last_name; DEPARTMENT_ID LAST_NAME SALARY FV ------------- ------------------------- ---------- ------------------------- 90 De Haan 17000 De Haan 90 King 24000 De Haan 90 Kochhar 17000 De Haan
The following example shows how to make the FIRST_VALUE
function deterministic by ordering on a unique key.
SELECT department_id, last_name, salary, hire_date, FIRST_VALUE(last_name) (ORDER BY salary ASC, hire_date ROWS UNBOUNDED PRECEDING) AS fv FROM (SELECT * FROM employees WHERE department_id = 90 ORDER BY employee_id DESC) ORDER BY last_name; DEPARTMENT_ID LAST_NAME SALARY HIRE_DATE FV ------------- --------------- ---------- --------- ------------------------- 90 De Haan 17000 13-JAN-01 De Haan 90 King 24000 17-JUN-03 De Haan 90 Kochhar 17000 21-SEP-05 De Haan
When you use a logical offset (RANGE
instead of ROWS
), the function is deterministic. When duplicates are found for the ORDER
BY
expression, the FIRST_VALUE
is the lowest value of expr
:
SELECT department_id, last_name, salary, FIRST_VALUE(last_name) OVER (ORDER BY salary ASC RANGE UNBOUNDED PRECEDING) AS lowest_sal FROM (SELECT * FROM employees WHERE department_id = 90 ORDER BY employee_id); DEPARTMENT_ID LAST_NAME SALARY LOWEST_SAL ------------- ------------------------- ---------- ------------------------- 90 De Haan 17000 De Haan 90 Kochhar 17000 De Haan 90 King 24000 De Haan